3.1.7 \(\int (a+b x)^4 \log (e (f (a+b x)^p (c+d x)^q)^r) \, dx\) [7]

3.1.7.1 Optimal result
3.1.7.2 Mathematica [A] (verified)
3.1.7.3 Rubi [A] (verified)
3.1.7.4 Maple [F]
3.1.7.5 Fricas [B] (verification not implemented)
3.1.7.6 Sympy [F(-1)]
3.1.7.7 Maxima [B] (verification not implemented)
3.1.7.8 Giac [B] (verification not implemented)
3.1.7.9 Mupad [B] (verification not implemented)

3.1.7.1 Optimal result

Integrand size = 29, antiderivative size = 201 \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=-\frac {(b c-a d)^4 q r x}{5 d^4}+\frac {(b c-a d)^3 q r (a+b x)^2}{10 b d^3}-\frac {(b c-a d)^2 q r (a+b x)^3}{15 b d^2}+\frac {(b c-a d) q r (a+b x)^4}{20 b d}-\frac {p r (a+b x)^5}{25 b}-\frac {q r (a+b x)^5}{25 b}+\frac {(b c-a d)^5 q r \log (c+d x)}{5 b d^5}+\frac {(a+b x)^5 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{5 b} \]

output
-1/5*(-a*d+b*c)^4*q*r*x/d^4+1/10*(-a*d+b*c)^3*q*r*(b*x+a)^2/b/d^3-1/15*(-a 
*d+b*c)^2*q*r*(b*x+a)^3/b/d^2+1/20*(-a*d+b*c)*q*r*(b*x+a)^4/b/d-1/25*p*r*( 
b*x+a)^5/b-1/25*q*r*(b*x+a)^5/b+1/5*(-a*d+b*c)^5*q*r*ln(d*x+c)/b/d^5+1/5*( 
b*x+a)^5*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)/b
 
3.1.7.2 Mathematica [A] (verified)

Time = 0.19 (sec) , antiderivative size = 185, normalized size of antiderivative = 0.92 \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\frac {-\frac {r \left (60 b d (b c-a d)^4 (p+5 q) x-60 b^2 (b c-a d)^3 (2 p+5 q) (c+d x)^2+40 b^3 (b c-a d)^2 (3 p+5 q) (c+d x)^3-15 b^4 (b c-a d) (4 p+5 q) (c+d x)^4+12 b^5 (p+q) (c+d x)^5-60 (b c-a d)^5 q \log (c+d x)\right )}{60 d^5}+(a+b x)^5 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{5 b} \]

input
Integrate[(a + b*x)^4*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r],x]
 
output
(-1/60*(r*(60*b*d*(b*c - a*d)^4*(p + 5*q)*x - 60*b^2*(b*c - a*d)^3*(2*p + 
5*q)*(c + d*x)^2 + 40*b^3*(b*c - a*d)^2*(3*p + 5*q)*(c + d*x)^3 - 15*b^4*( 
b*c - a*d)*(4*p + 5*q)*(c + d*x)^4 + 12*b^5*(p + q)*(c + d*x)^5 - 60*(b*c 
- a*d)^5*q*Log[c + d*x]))/d^5 + (a + b*x)^5*Log[e*(f*(a + b*x)^p*(c + d*x) 
^q)^r])/(5*b)
 
3.1.7.3 Rubi [A] (verified)

Time = 0.34 (sec) , antiderivative size = 184, normalized size of antiderivative = 0.92, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.138, Rules used = {2981, 17, 49, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx\)

\(\Big \downarrow \) 2981

\(\displaystyle -\frac {d q r \int \frac {(a+b x)^5}{c+d x}dx}{5 b}-\frac {1}{5} p r \int (a+b x)^4dx+\frac {(a+b x)^5 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{5 b}\)

\(\Big \downarrow \) 17

\(\displaystyle -\frac {d q r \int \frac {(a+b x)^5}{c+d x}dx}{5 b}+\frac {(a+b x)^5 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{5 b}-\frac {p r (a+b x)^5}{25 b}\)

\(\Big \downarrow \) 49

\(\displaystyle -\frac {d q r \int \left (\frac {(a d-b c)^5}{d^5 (c+d x)}+\frac {b (b c-a d)^4}{d^5}+\frac {b (a+b x)^4}{d}-\frac {b (b c-a d) (a+b x)^3}{d^2}+\frac {b (b c-a d)^2 (a+b x)^2}{d^3}-\frac {b (b c-a d)^3 (a+b x)}{d^4}\right )dx}{5 b}+\frac {(a+b x)^5 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{5 b}-\frac {p r (a+b x)^5}{25 b}\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {d q r \left (-\frac {(b c-a d)^5 \log (c+d x)}{d^6}+\frac {b x (b c-a d)^4}{d^5}-\frac {(a+b x)^2 (b c-a d)^3}{2 d^4}+\frac {(a+b x)^3 (b c-a d)^2}{3 d^3}-\frac {(a+b x)^4 (b c-a d)}{4 d^2}+\frac {(a+b x)^5}{5 d}\right )}{5 b}+\frac {(a+b x)^5 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{5 b}-\frac {p r (a+b x)^5}{25 b}\)

input
Int[(a + b*x)^4*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r],x]
 
output
-1/25*(p*r*(a + b*x)^5)/b - (d*q*r*((b*(b*c - a*d)^4*x)/d^5 - ((b*c - a*d) 
^3*(a + b*x)^2)/(2*d^4) + ((b*c - a*d)^2*(a + b*x)^3)/(3*d^3) - ((b*c - a* 
d)*(a + b*x)^4)/(4*d^2) + (a + b*x)^5/(5*d) - ((b*c - a*d)^5*Log[c + d*x]) 
/d^6))/(5*b) + ((a + b*x)^5*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r])/(5*b)
 

3.1.7.3.1 Defintions of rubi rules used

rule 17
Int[(c_.)*((a_.) + (b_.)*(x_))^(m_.), x_Symbol] :> Simp[c*((a + b*x)^(m + 1 
)/(b*(m + 1))), x] /; FreeQ[{a, b, c, m}, x] && NeQ[m, -1]
 

rule 49
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int 
[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] 
&& IGtQ[m, 0] && IGtQ[m + n + 2, 0]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2981
Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.)) 
^(r_.)]*((g_.) + (h_.)*(x_))^(m_.), x_Symbol] :> Simp[(g + h*x)^(m + 1)*(Lo 
g[e*(f*(a + b*x)^p*(c + d*x)^q)^r]/(h*(m + 1))), x] + (-Simp[b*p*(r/(h*(m + 
 1)))   Int[(g + h*x)^(m + 1)/(a + b*x), x], x] - Simp[d*q*(r/(h*(m + 1))) 
  Int[(g + h*x)^(m + 1)/(c + d*x), x], x]) /; FreeQ[{a, b, c, d, e, f, g, h 
, m, p, q, r}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1]
 
3.1.7.4 Maple [F]

\[\int \left (b x +a \right )^{4} \ln \left (e \left (f \left (b x +a \right )^{p} \left (d x +c \right )^{q}\right )^{r}\right )d x\]

input
int((b*x+a)^4*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r),x)
 
output
int((b*x+a)^4*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r),x)
 
3.1.7.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 624 vs. \(2 (185) = 370\).

Time = 0.32 (sec) , antiderivative size = 624, normalized size of antiderivative = 3.10 \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=-\frac {12 \, {\left (b^{5} d^{5} p + b^{5} d^{5} q\right )} r x^{5} + 15 \, {\left (4 \, a b^{4} d^{5} p - {\left (b^{5} c d^{4} - 5 \, a b^{4} d^{5}\right )} q\right )} r x^{4} + 20 \, {\left (6 \, a^{2} b^{3} d^{5} p + {\left (b^{5} c^{2} d^{3} - 5 \, a b^{4} c d^{4} + 10 \, a^{2} b^{3} d^{5}\right )} q\right )} r x^{3} + 30 \, {\left (4 \, a^{3} b^{2} d^{5} p - {\left (b^{5} c^{3} d^{2} - 5 \, a b^{4} c^{2} d^{3} + 10 \, a^{2} b^{3} c d^{4} - 10 \, a^{3} b^{2} d^{5}\right )} q\right )} r x^{2} + 60 \, {\left (a^{4} b d^{5} p + {\left (b^{5} c^{4} d - 5 \, a b^{4} c^{3} d^{2} + 10 \, a^{2} b^{3} c^{2} d^{3} - 10 \, a^{3} b^{2} c d^{4} + 5 \, a^{4} b d^{5}\right )} q\right )} r x - 60 \, {\left (b^{5} d^{5} p r x^{5} + 5 \, a b^{4} d^{5} p r x^{4} + 10 \, a^{2} b^{3} d^{5} p r x^{3} + 10 \, a^{3} b^{2} d^{5} p r x^{2} + 5 \, a^{4} b d^{5} p r x + a^{5} d^{5} p r\right )} \log \left (b x + a\right ) - 60 \, {\left (b^{5} d^{5} q r x^{5} + 5 \, a b^{4} d^{5} q r x^{4} + 10 \, a^{2} b^{3} d^{5} q r x^{3} + 10 \, a^{3} b^{2} d^{5} q r x^{2} + 5 \, a^{4} b d^{5} q r x + {\left (b^{5} c^{5} - 5 \, a b^{4} c^{4} d + 10 \, a^{2} b^{3} c^{3} d^{2} - 10 \, a^{3} b^{2} c^{2} d^{3} + 5 \, a^{4} b c d^{4}\right )} q r\right )} \log \left (d x + c\right ) - 60 \, {\left (b^{5} d^{5} x^{5} + 5 \, a b^{4} d^{5} x^{4} + 10 \, a^{2} b^{3} d^{5} x^{3} + 10 \, a^{3} b^{2} d^{5} x^{2} + 5 \, a^{4} b d^{5} x\right )} \log \left (e\right ) - 60 \, {\left (b^{5} d^{5} r x^{5} + 5 \, a b^{4} d^{5} r x^{4} + 10 \, a^{2} b^{3} d^{5} r x^{3} + 10 \, a^{3} b^{2} d^{5} r x^{2} + 5 \, a^{4} b d^{5} r x\right )} \log \left (f\right )}{300 \, b d^{5}} \]

input
integrate((b*x+a)^4*log(e*(f*(b*x+a)^p*(d*x+c)^q)^r),x, algorithm="fricas" 
)
 
output
-1/300*(12*(b^5*d^5*p + b^5*d^5*q)*r*x^5 + 15*(4*a*b^4*d^5*p - (b^5*c*d^4 
- 5*a*b^4*d^5)*q)*r*x^4 + 20*(6*a^2*b^3*d^5*p + (b^5*c^2*d^3 - 5*a*b^4*c*d 
^4 + 10*a^2*b^3*d^5)*q)*r*x^3 + 30*(4*a^3*b^2*d^5*p - (b^5*c^3*d^2 - 5*a*b 
^4*c^2*d^3 + 10*a^2*b^3*c*d^4 - 10*a^3*b^2*d^5)*q)*r*x^2 + 60*(a^4*b*d^5*p 
 + (b^5*c^4*d - 5*a*b^4*c^3*d^2 + 10*a^2*b^3*c^2*d^3 - 10*a^3*b^2*c*d^4 + 
5*a^4*b*d^5)*q)*r*x - 60*(b^5*d^5*p*r*x^5 + 5*a*b^4*d^5*p*r*x^4 + 10*a^2*b 
^3*d^5*p*r*x^3 + 10*a^3*b^2*d^5*p*r*x^2 + 5*a^4*b*d^5*p*r*x + a^5*d^5*p*r) 
*log(b*x + a) - 60*(b^5*d^5*q*r*x^5 + 5*a*b^4*d^5*q*r*x^4 + 10*a^2*b^3*d^5 
*q*r*x^3 + 10*a^3*b^2*d^5*q*r*x^2 + 5*a^4*b*d^5*q*r*x + (b^5*c^5 - 5*a*b^4 
*c^4*d + 10*a^2*b^3*c^3*d^2 - 10*a^3*b^2*c^2*d^3 + 5*a^4*b*c*d^4)*q*r)*log 
(d*x + c) - 60*(b^5*d^5*x^5 + 5*a*b^4*d^5*x^4 + 10*a^2*b^3*d^5*x^3 + 10*a^ 
3*b^2*d^5*x^2 + 5*a^4*b*d^5*x)*log(e) - 60*(b^5*d^5*r*x^5 + 5*a*b^4*d^5*r* 
x^4 + 10*a^2*b^3*d^5*r*x^3 + 10*a^3*b^2*d^5*r*x^2 + 5*a^4*b*d^5*r*x)*log(f 
))/(b*d^5)
 
3.1.7.6 Sympy [F(-1)]

Timed out. \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\text {Timed out} \]

input
integrate((b*x+a)**4*ln(e*(f*(b*x+a)**p*(d*x+c)**q)**r),x)
 
output
Timed out
 
3.1.7.7 Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 395 vs. \(2 (185) = 370\).

Time = 0.20 (sec) , antiderivative size = 395, normalized size of antiderivative = 1.97 \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\frac {1}{5} \, {\left (b^{4} x^{5} + 5 \, a b^{3} x^{4} + 10 \, a^{2} b^{2} x^{3} + 10 \, a^{3} b x^{2} + 5 \, a^{4} x\right )} \log \left (\left ({\left (b x + a\right )}^{p} {\left (d x + c\right )}^{q} f\right )^{r} e\right ) + \frac {{\left (\frac {60 \, a^{5} f p \log \left (b x + a\right )}{b} - \frac {12 \, b^{4} d^{4} f {\left (p + q\right )} x^{5} + 15 \, {\left (a b^{3} d^{4} f {\left (4 \, p + 5 \, q\right )} - b^{4} c d^{3} f q\right )} x^{4} + 20 \, {\left (2 \, a^{2} b^{2} d^{4} f {\left (3 \, p + 5 \, q\right )} + b^{4} c^{2} d^{2} f q - 5 \, a b^{3} c d^{3} f q\right )} x^{3} + 30 \, {\left (2 \, a^{3} b d^{4} f {\left (2 \, p + 5 \, q\right )} - b^{4} c^{3} d f q + 5 \, a b^{3} c^{2} d^{2} f q - 10 \, a^{2} b^{2} c d^{3} f q\right )} x^{2} + 60 \, {\left (a^{4} d^{4} f {\left (p + 5 \, q\right )} + b^{4} c^{4} f q - 5 \, a b^{3} c^{3} d f q + 10 \, a^{2} b^{2} c^{2} d^{2} f q - 10 \, a^{3} b c d^{3} f q\right )} x}{d^{4}} + \frac {60 \, {\left (b^{4} c^{5} f q - 5 \, a b^{3} c^{4} d f q + 10 \, a^{2} b^{2} c^{3} d^{2} f q - 10 \, a^{3} b c^{2} d^{3} f q + 5 \, a^{4} c d^{4} f q\right )} \log \left (d x + c\right )}{d^{5}}\right )} r}{300 \, f} \]

input
integrate((b*x+a)^4*log(e*(f*(b*x+a)^p*(d*x+c)^q)^r),x, algorithm="maxima" 
)
 
output
1/5*(b^4*x^5 + 5*a*b^3*x^4 + 10*a^2*b^2*x^3 + 10*a^3*b*x^2 + 5*a^4*x)*log( 
((b*x + a)^p*(d*x + c)^q*f)^r*e) + 1/300*(60*a^5*f*p*log(b*x + a)/b - (12* 
b^4*d^4*f*(p + q)*x^5 + 15*(a*b^3*d^4*f*(4*p + 5*q) - b^4*c*d^3*f*q)*x^4 + 
 20*(2*a^2*b^2*d^4*f*(3*p + 5*q) + b^4*c^2*d^2*f*q - 5*a*b^3*c*d^3*f*q)*x^ 
3 + 30*(2*a^3*b*d^4*f*(2*p + 5*q) - b^4*c^3*d*f*q + 5*a*b^3*c^2*d^2*f*q - 
10*a^2*b^2*c*d^3*f*q)*x^2 + 60*(a^4*d^4*f*(p + 5*q) + b^4*c^4*f*q - 5*a*b^ 
3*c^3*d*f*q + 10*a^2*b^2*c^2*d^2*f*q - 10*a^3*b*c*d^3*f*q)*x)/d^4 + 60*(b^ 
4*c^5*f*q - 5*a*b^3*c^4*d*f*q + 10*a^2*b^2*c^3*d^2*f*q - 10*a^3*b*c^2*d^3* 
f*q + 5*a^4*c*d^4*f*q)*log(d*x + c)/d^5)*r/f
 
3.1.7.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 570 vs. \(2 (185) = 370\).

Time = 10.72 (sec) , antiderivative size = 570, normalized size of antiderivative = 2.84 \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\frac {a^{5} p r \log \left (b x + a\right )}{5 \, b} - \frac {1}{25} \, {\left (b^{4} p r + b^{4} q r - 5 \, b^{4} r \log \left (f\right ) - 5 \, b^{4} \log \left (e\right )\right )} x^{5} - \frac {{\left (4 \, a b^{3} d p r - b^{4} c q r + 5 \, a b^{3} d q r - 20 \, a b^{3} d r \log \left (f\right ) - 20 \, a b^{3} d \log \left (e\right )\right )} x^{4}}{20 \, d} - \frac {{\left (6 \, a^{2} b^{2} d^{2} p r + b^{4} c^{2} q r - 5 \, a b^{3} c d q r + 10 \, a^{2} b^{2} d^{2} q r - 30 \, a^{2} b^{2} d^{2} r \log \left (f\right ) - 30 \, a^{2} b^{2} d^{2} \log \left (e\right )\right )} x^{3}}{15 \, d^{2}} + \frac {1}{5} \, {\left (b^{4} p r x^{5} + 5 \, a b^{3} p r x^{4} + 10 \, a^{2} b^{2} p r x^{3} + 10 \, a^{3} b p r x^{2} + 5 \, a^{4} p r x\right )} \log \left (b x + a\right ) + \frac {1}{5} \, {\left (b^{4} q r x^{5} + 5 \, a b^{3} q r x^{4} + 10 \, a^{2} b^{2} q r x^{3} + 10 \, a^{3} b q r x^{2} + 5 \, a^{4} q r x\right )} \log \left (d x + c\right ) - \frac {{\left (4 \, a^{3} b d^{3} p r - b^{4} c^{3} q r + 5 \, a b^{3} c^{2} d q r - 10 \, a^{2} b^{2} c d^{2} q r + 10 \, a^{3} b d^{3} q r - 20 \, a^{3} b d^{3} r \log \left (f\right ) - 20 \, a^{3} b d^{3} \log \left (e\right )\right )} x^{2}}{10 \, d^{3}} - \frac {{\left (a^{4} d^{4} p r + b^{4} c^{4} q r - 5 \, a b^{3} c^{3} d q r + 10 \, a^{2} b^{2} c^{2} d^{2} q r - 10 \, a^{3} b c d^{3} q r + 5 \, a^{4} d^{4} q r - 5 \, a^{4} d^{4} r \log \left (f\right ) - 5 \, a^{4} d^{4} \log \left (e\right )\right )} x}{5 \, d^{4}} + \frac {{\left (b^{4} c^{5} q r - 5 \, a b^{3} c^{4} d q r + 10 \, a^{2} b^{2} c^{3} d^{2} q r - 10 \, a^{3} b c^{2} d^{3} q r + 5 \, a^{4} c d^{4} q r\right )} \log \left (-d x - c\right )}{5 \, d^{5}} \]

input
integrate((b*x+a)^4*log(e*(f*(b*x+a)^p*(d*x+c)^q)^r),x, algorithm="giac")
 
output
1/5*a^5*p*r*log(b*x + a)/b - 1/25*(b^4*p*r + b^4*q*r - 5*b^4*r*log(f) - 5* 
b^4*log(e))*x^5 - 1/20*(4*a*b^3*d*p*r - b^4*c*q*r + 5*a*b^3*d*q*r - 20*a*b 
^3*d*r*log(f) - 20*a*b^3*d*log(e))*x^4/d - 1/15*(6*a^2*b^2*d^2*p*r + b^4*c 
^2*q*r - 5*a*b^3*c*d*q*r + 10*a^2*b^2*d^2*q*r - 30*a^2*b^2*d^2*r*log(f) - 
30*a^2*b^2*d^2*log(e))*x^3/d^2 + 1/5*(b^4*p*r*x^5 + 5*a*b^3*p*r*x^4 + 10*a 
^2*b^2*p*r*x^3 + 10*a^3*b*p*r*x^2 + 5*a^4*p*r*x)*log(b*x + a) + 1/5*(b^4*q 
*r*x^5 + 5*a*b^3*q*r*x^4 + 10*a^2*b^2*q*r*x^3 + 10*a^3*b*q*r*x^2 + 5*a^4*q 
*r*x)*log(d*x + c) - 1/10*(4*a^3*b*d^3*p*r - b^4*c^3*q*r + 5*a*b^3*c^2*d*q 
*r - 10*a^2*b^2*c*d^2*q*r + 10*a^3*b*d^3*q*r - 20*a^3*b*d^3*r*log(f) - 20* 
a^3*b*d^3*log(e))*x^2/d^3 - 1/5*(a^4*d^4*p*r + b^4*c^4*q*r - 5*a*b^3*c^3*d 
*q*r + 10*a^2*b^2*c^2*d^2*q*r - 10*a^3*b*c*d^3*q*r + 5*a^4*d^4*q*r - 5*a^4 
*d^4*r*log(f) - 5*a^4*d^4*log(e))*x/d^4 + 1/5*(b^4*c^5*q*r - 5*a*b^3*c^4*d 
*q*r + 10*a^2*b^2*c^3*d^2*q*r - 10*a^3*b*c^2*d^3*q*r + 5*a^4*c*d^4*q*r)*lo 
g(-d*x - c)/d^5
 
3.1.7.9 Mupad [B] (verification not implemented)

Time = 1.69 (sec) , antiderivative size = 886, normalized size of antiderivative = 4.41 \[ \int (a+b x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\ln \left (e\,{\left (f\,{\left (a+b\,x\right )}^p\,{\left (c+d\,x\right )}^q\right )}^r\right )\,\left (a^4\,x+2\,a^3\,b\,x^2+2\,a^2\,b^2\,x^3+a\,b^3\,x^4+\frac {b^4\,x^5}{5}\right )-x^4\,\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{20\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{100\,d}\right )+x^3\,\left (\frac {\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{5\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{25\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{15\,b\,d}-\frac {a\,b^2\,r\,\left (2\,a\,d\,p+b\,c\,p+3\,a\,d\,q\right )}{3\,d}+\frac {a\,b^3\,c\,r\,\left (p+q\right )}{15\,d}\right )-x\,\left (\frac {a^3\,r\,\left (a\,d\,p+2\,b\,c\,p+3\,a\,d\,q\right )}{d}-\frac {\left (5\,a\,d+5\,b\,c\right )\,\left (\frac {\left (5\,a\,d+5\,b\,c\right )\,\left (\frac {\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{5\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{25\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{5\,b\,d}-\frac {a\,b^2\,r\,\left (2\,a\,d\,p+b\,c\,p+3\,a\,d\,q\right )}{d}+\frac {a\,b^3\,c\,r\,\left (p+q\right )}{5\,d}\right )}{5\,b\,d}-\frac {a\,c\,\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{5\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{25\,d}\right )}{b\,d}+\frac {2\,a^2\,b\,r\,\left (a\,d\,p+b\,c\,p+2\,a\,d\,q\right )}{d}\right )}{5\,b\,d}+\frac {a\,c\,\left (\frac {\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{5\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{25\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{5\,b\,d}-\frac {a\,b^2\,r\,\left (2\,a\,d\,p+b\,c\,p+3\,a\,d\,q\right )}{d}+\frac {a\,b^3\,c\,r\,\left (p+q\right )}{5\,d}\right )}{b\,d}\right )-x^2\,\left (\frac {\left (5\,a\,d+5\,b\,c\right )\,\left (\frac {\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{5\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{25\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{5\,b\,d}-\frac {a\,b^2\,r\,\left (2\,a\,d\,p+b\,c\,p+3\,a\,d\,q\right )}{d}+\frac {a\,b^3\,c\,r\,\left (p+q\right )}{5\,d}\right )}{10\,b\,d}-\frac {a\,c\,\left (\frac {b^3\,r\,\left (5\,a\,d\,p+b\,c\,p+6\,a\,d\,q\right )}{5\,d}-\frac {b^3\,r\,\left (p+q\right )\,\left (5\,a\,d+5\,b\,c\right )}{25\,d}\right )}{2\,b\,d}+\frac {a^2\,b\,r\,\left (a\,d\,p+b\,c\,p+2\,a\,d\,q\right )}{d}\right )+\frac {\ln \left (c+d\,x\right )\,\left (q\,r\,a^4\,c\,d^4-2\,q\,r\,a^3\,b\,c^2\,d^3+2\,q\,r\,a^2\,b^2\,c^3\,d^2-q\,r\,a\,b^3\,c^4\,d+\frac {q\,r\,b^4\,c^5}{5}\right )}{d^5}-\frac {b^4\,r\,x^5\,\left (p+q\right )}{25}+\frac {a^5\,p\,r\,\ln \left (a+b\,x\right )}{5\,b} \]

input
int(log(e*(f*(a + b*x)^p*(c + d*x)^q)^r)*(a + b*x)^4,x)
 
output
log(e*(f*(a + b*x)^p*(c + d*x)^q)^r)*(a^4*x + (b^4*x^5)/5 + 2*a^3*b*x^2 + 
a*b^3*x^4 + 2*a^2*b^2*x^3) - x^4*((b^3*r*(5*a*d*p + b*c*p + 6*a*d*q))/(20* 
d) - (b^3*r*(p + q)*(5*a*d + 5*b*c))/(100*d)) + x^3*((((b^3*r*(5*a*d*p + b 
*c*p + 6*a*d*q))/(5*d) - (b^3*r*(p + q)*(5*a*d + 5*b*c))/(25*d))*(5*a*d + 
5*b*c))/(15*b*d) - (a*b^2*r*(2*a*d*p + b*c*p + 3*a*d*q))/(3*d) + (a*b^3*c* 
r*(p + q))/(15*d)) - x*((a^3*r*(a*d*p + 2*b*c*p + 3*a*d*q))/d - ((5*a*d + 
5*b*c)*(((5*a*d + 5*b*c)*((((b^3*r*(5*a*d*p + b*c*p + 6*a*d*q))/(5*d) - (b 
^3*r*(p + q)*(5*a*d + 5*b*c))/(25*d))*(5*a*d + 5*b*c))/(5*b*d) - (a*b^2*r* 
(2*a*d*p + b*c*p + 3*a*d*q))/d + (a*b^3*c*r*(p + q))/(5*d)))/(5*b*d) - (a* 
c*((b^3*r*(5*a*d*p + b*c*p + 6*a*d*q))/(5*d) - (b^3*r*(p + q)*(5*a*d + 5*b 
*c))/(25*d)))/(b*d) + (2*a^2*b*r*(a*d*p + b*c*p + 2*a*d*q))/d))/(5*b*d) + 
(a*c*((((b^3*r*(5*a*d*p + b*c*p + 6*a*d*q))/(5*d) - (b^3*r*(p + q)*(5*a*d 
+ 5*b*c))/(25*d))*(5*a*d + 5*b*c))/(5*b*d) - (a*b^2*r*(2*a*d*p + b*c*p + 3 
*a*d*q))/d + (a*b^3*c*r*(p + q))/(5*d)))/(b*d)) - x^2*(((5*a*d + 5*b*c)*(( 
((b^3*r*(5*a*d*p + b*c*p + 6*a*d*q))/(5*d) - (b^3*r*(p + q)*(5*a*d + 5*b*c 
))/(25*d))*(5*a*d + 5*b*c))/(5*b*d) - (a*b^2*r*(2*a*d*p + b*c*p + 3*a*d*q) 
)/d + (a*b^3*c*r*(p + q))/(5*d)))/(10*b*d) - (a*c*((b^3*r*(5*a*d*p + b*c*p 
 + 6*a*d*q))/(5*d) - (b^3*r*(p + q)*(5*a*d + 5*b*c))/(25*d)))/(2*b*d) + (a 
^2*b*r*(a*d*p + b*c*p + 2*a*d*q))/d) + (log(c + d*x)*((b^4*c^5*q*r)/5 + a^ 
4*c*d^4*q*r + 2*a^2*b^2*c^3*d^2*q*r - a*b^3*c^4*d*q*r - 2*a^3*b*c^2*d^3...